Exercises – Long Day#
Exercise 1: The number \(i\)#
In this exercise you will acquire some initial insight into the fundamentals of the complex numbers.
Question a#
What are \(i^2\), \(i^3\), \(i^4\), \(i^5\), \((-i)^2\), \((-i)^3\), \((-i)^4\), and \((-i)^{-5}\,\)? (Note the negative exponent in the last number.)
Hint
If you are in doubt about how to simplify \(i^2\), then see Definition 4.1.1 in the textbook.
Answer
Question b#
What is the real part and the imaginary part of the three complex numbers \(10+i\), \(3\), and \(i\)? What about the real part and imaginary part of the number \(-5-i7\,\)?
Hint
If you are in doubt about what the real part and the imaginary part of a complex number are, then read the bit in the textbook between Definition 3.1.1 to Example 3.1.1.
Remember that the imaginary unit \(i\) is not itself included in the imaginary part (in fact, the imaginary part is real).
Answer
\(10+i\): The real part is \(10\) and the imaginary part \(1\).
\(3\): The real part is \(3\) and the imaginary part \(0\).
\(i\): The real part is \(0\) and the imaginary part \(1\).
\(-5-i7\): The real part is \(-5\) and the imaginary part \(-7\).
Question c#
What are \(\mathrm{Re}(-5-7i)\) and \(\mathrm{Im}(-5-7i)\)?
Answer
\(\mathrm{Re}(-5-7i)=-5\) and \(\mathrm{Im}(-5-7i)=-7.\)
Question d#
Write the complex numbers \(\,7i-5\,\), \(\,i(7i-5)\,\), and \(\,i(7i-5)i\,\) in rectangular form.
Hint
Definition 4.2.2 explains how two complex numbers are multiplied.
Answer
Exercise 2: Brackets and the Hierarchy of the Arithmetic Operations#
Question a#
Given the number \(\,\,z=3(i-10)-5(7-2i)-i(3i-5)+3i(i-5)\,,\) determine the rectangular form of \(z\,.\)
Hint
In expressions where both multiplication and addition/subtraction are involved, multiplicaton is to be performed first.
Answer
Question b#
We are given the numbers
Write the number \(\,z=a+ib\,\) in rectangular form.
Answer
Exercise 3: Fractions#
Question a#
Determine the real part and the imaginary part of \((-2+3i)/i\) and bring the number to its rectangular form.
Hint
You can find som examples of how to rewrite a fraction of complex numbers to its rectangular form in Example 4.2.3 in the textbook.
Answer
Question b#
Reduce the following expression and bring it to its rectangular form:
Hint
The easiest might be to start with the second fraction and rewrite it to rectangular form. For this you can use an approach similar to what took place in Question a.
Answer
Exercise 4: The Complex Plane#
Question a#
Consider the following ten numbers: \(-2,\,0,\,i,\,2-i,\,1+2i,\,1,\,-2+3i,\,-5i,\,3,\,\) and \(\,-1-2i\,.\)
Which of them are complex, which are real, and which are purely imaginary?
Draw the ten numbers in the complex plane.
Hint
If you need to brush up on how to draw numbers in the complex plane or on what exactly “purely imaginary” means then have a look in the textbook’s Section 4.1, in particular the text after Definition 4.1.1.
Answer
All ten numbers are complex numbers. The numbers \(-2,0,1,3\) are real numbers. The numbers \(0,i,-5i\) are purely imaginary numbers.
Note that \(0\) can be considered as both a real number and a purely imaginary number since it is located both on the real axis and on the imaginary axis.
Question b#
We are given the number \(z=4+i\,\).
Draw the four numbers \(\,z\,,\,iz\,,\,i^2z\,\), and \(\,i^3z\,\) in the complex plane.
What happens geometrically in the complex plane when a complex number is multiplied by \(i\,\)?
And divided by \(i\,\)?
Exercise 5: Fundamental Arithmetics#
Question a#
Determine using elementary calculations the rectangular form of the following complex numbers.
\((5+i)(1+9i).\)
\(i+i^2+i^3+i^4.\)
\(\displaystyle{\frac{1}{1+3i}+\frac{1}{(1+3i)^2}}.\)
\(\displaystyle{\frac{1}{(1+i)^4}}.\)
\(\displaystyle{\frac{5+i}{2-2i}}.\)
\(\displaystyle{\frac{3i}{4}}\,\) and \(\displaystyle{\frac{i2}{4}}.\)
Hint
To simplify a fraction where both numerator and denominator are complex numbers in rectangular form, Equation (4.2) in the textbook will show helpful. See also Example 4.2.3.
Answer
\(-4+46i\)
\(0\)
\(\frac{1}{50} -\frac{9}{25} i\)
\(- \frac{1}{4}\)
\(1+ \frac{3}{2}i\)
\(\frac{3}{4} i\) and \(\frac{1}{2} i\).
Question b#
We are given two real numbers \(a\) and \(b\,\) that are not both equal to \(0\).
Why is the number \(\,\,\displaystyle{\frac{1}{a+ib}}\,\,\) not in rectangular form?
Compute \(\mathrm{Re}\displaystyle{\left(\frac{1}{a+ib}\right)}\,\) and \(\mathrm{Im}\displaystyle{\left(\frac{1}{a+ib}\right)}\,\,\).
Answer
\(\mathrm{Re}\displaystyle{\left(\frac{1}{a+ib}\right)}\, = \frac{a}{a^2+b^2}\) and \(\mathrm{Im}\displaystyle{\left(\frac{1}{a+ib}\right)} = -\frac{b}{a^2+b^2}\).
Exercise 6: Conjugation#
In Definition 4.2.3 the complex conjugate \(\overline{z}\) of a complex number \(z\) is defined. You might want to read this definition again before continuing so that you have the precise meaning of the notation \(\overline{z}\) fresh in mind.
Question a#
Show that \(\overline{\overline{2+3i}}=2+3i\) and that \(\overline{(2+3i)\cdot (2+3i)}=\overline{2+3i}\cdot \overline{2+3i}\). Now show that in general we have \(\,\overline{\overline{z}}=z\,\) and \(\,\overline{z_1\cdot z_2}=\overline{z_1}\cdot\overline{z_2}\,\) for all complex numbers \(z\), \(z_1\), and \(z_2\).
Hint
If \(z=a+bi\) is a complex number in rectangular form, what will then happen if you perform complex conjugation twice (two times) in a row? In a similar manner, try computing both \(\,\overline{z_1\cdot z_2}\) and \(\overline{z_1}\cdot\overline{z_2}\,\) where \(z_1=a+bi\) and \(z_2=c+di\) are the numbers \(z_1\) and \(z_2\) written in rectangular form.
Question b#
Let \(z=a+ib\neq 0\) be a given non-zero complex number. Which other complex number corresponds to the mirror image of \(z\) about
the origin in the complex plane,
the real axis,
the imaginary axis, and
a line passing through the origin with a slope of \(1\)?
Provide the answers both in rectangular form and as expressions written in terms of \(z\), \(\overline{z}\), and \(i\).
Hint
Start with a clear overview by drawing everything mentioned in the complex plane.
Answer
Rectangular form: \(-a-bi\). Expression: \(-z\).
Rectangular form: \(a-bi\). Expression: \(\overline{z}\).
Rectangular form: \(-a+bi\). Expression: \(-\overline{z}\).
Rectangular form: \(b+ai\). Expression: \(i\cdot \overline{z}\).
Exercise 7: Absolute Value#
The absolute value \(\,\left|z\right|\,\) of a complex number \(z\) can geometrically be interpretted as the distance between \(0\) (the origin) and \(z\) in the complex plane. See Figure 4.4 in the textbook for an illustration. The absolute value is also called the modulus in the context of complex numbers.
Question a#
We are given real numbers \(a,b\) and a complex number in rectangular form \(\,z=a+ib\,.\) Compute \(\,\left|z\right|\,.\) What is \(|2+3i|\)?
Answer
\(|z|=\sqrt{a^2+b^2}\) and \(|2+3i|=\sqrt{2^2+3^2}=\sqrt{13}\).
Question b#
Investigate which geometric meaning the absolute value \(\,\left|z_1-z_2\right|\,\) has for two arbitrary complex numbers \(\,z_1\,\) and \(\,z_2\,\). Illustrate with examples.
Answer
\(\,\left|z_1-z_2\right|\,\) is the distance between \(z_1\) and \(z_2\) in the complex plane.
Question c#
A set in the complex plane is given by
Provide a geometric description of the set.
Answer
The set describes a circle in the complex plane centred at the number \(1\) with a radius of \(3\).
Exercise 8: Sets in the Complex Plane#
In the complex plane we consider the set of numbers \(\,M=\left\{z\,|\,\,|z-1+2i|\leq 3\,\right\}\,.\)
Question a#
Describe \(M\) and sketch \(M\) in the complex plane.
Question b#
Determine \(M \cap \mathbb{R}\), meaning the subset of \(\,M\,\) that contains all real numbers within \(M\).
Hint
First, sketch \(M \cap \mathbb{R}\) on your drawing from Question a.
Answer
Exercise 9: An Equation with Modulus#
Determine all complex numbers \(z\) that satisfy the equation \(|z-1|=|2z-3|\). Sketch the solution set in the complex plane.
Hint
It may be of help to write \(z\) as its rectangular form, \(z=a+bi\).
Hint
After having substituted in \(z=a+bi\), check that the equation \(|z-1|=|2z-3|\) holds if and only if \((a-1)^2+b^2=(2a-3)^2+(2b)^2\).
Answer
It can be shown that \((a-1)^2+b^2=(2a-3)^2+(2b)^2\) if and only if \((a-5/3)^2+b^2=(1/3)^2\). Hence the solution set forms a circle in the complex plane with a radius of \(1/3\) centred at the real number \(5/3\).
Are you Done with all Exercises?#
If it went too quick and you are eager for more then click here for some challenging optional extra exercises.